Friday, October 22, 2010

Combined Ch.22,23 HW: 7-9 (from Ch.23)

8 comments:

Prof. Koch said...

For these problems make sure you understand the sign conventions for mirrors summarized in Table 23.1 on p. 765 of SV8. I suggest you go carefully through the worked-out examples in Ch. 23.3.

Vito said...

I cannot figure out number 9 on the webassign

I have tried 1/p+1/q=1/f and it does not work.
My numbers:
n=1.70
r=10cm
p (as given): 20cm, 8.0cm, 4.00cm, 2.00cm.

When I do the problem for 20, I get the right answer. When I attempt to for the other portions I don't come close to the answer.

I 13.33 when I use p=8.0cm. someone help!

Thanks!
-Vito

Prof. Koch said...

Vito,

Are you sure you mean WA prob. 9 (which is SV8 prob. 22 in Ch. 23.)If so, you're using the wrong formula; this is not a thin-lens problem. Look at SV8, Fig. 23.15 for what this problem looks like. The relevant formula for such a problem is [23.7].

Prof. Koch

Vito said...

Professor,

I attempted to use that formula, first practicing with it using example 23.5 in the text. However, when I plugged in my numbers I got 7.0165. Now I know that my answer should be close to 79.0165, because it tells me I'm within 10% of the correct answer. I am not sure what I did wrong.

I set it up as such:
(1/8.0cm)+(1.70/q)=[(1.70-1.0)/10]

I don't understand what I'm doing wrong.

-Vito

Jen-TA said...

Vito,

You must used the exact value for the Index of Refraction of air which is n= 1.000293.

Hope this helps!

Vito said...

Jen! Thank you thank you thank you!!!!!!!!!!!!!!!!!!!!!!!! it worked!!!! =D

-Vito

Prof. Koch said...

Jen-TA and Vito, Thanks to Jen-TA for helping out, but I have to disagree with Jen-TA's comment. I can see the results of the WebAssign HW for each student. I looked at Vito's and worked his problem 9 (the randomization of input given to him by WA for SV8 Ch.23, Prob. 22) that you both discussed in the blog entries above. Using n=1 for air or n=1.000293 for air, I get the same result for q to 3 significant figures. This result agrees with the result that WA posts (WA gives it to 3 significant figures) for the Vito's problem when p=8 cm. That's why I disagree. Vito entered his answer with 6 significant figures that round off to the WA answer at 3 significant figures. It would be poor practice for WA to require use of n_air to 7 significant figures when SV8 routinely uses n=1 for air. Prof. Koch

Professor Stephens said...

We are aware of a bug in WebAssign HW problem 9 (SV8 Ch 23 Prob 22). This only occurs for people who are given randomized numbers n=1.60, R=12 cm, but it causes WA to mark all parts wrong. If this affects you, just enter what you believe are correct answers and we will adjust your score later. WebAssign sincerely apologizes for the error, and they are working hard to make it right. As far as we know, this only affects people who are given those specific numerical values.